Basis State
A basis state is one of a set of reference states — mutually orthogonal and normalized — from which every other quantum state can be built as a superposition.
What it means
A basis is a set of orthonormal states that spans the state space: any state |ψ⟩ can be written uniquely as a linear combination |ψ⟩ = Σᵢ cᵢ|i⟩ of the basis states |i⟩, with ⟨i|j⟩ = δᵢⱼ.For a single qubit, the standard choice is the computational basis {|0⟩, |1⟩}, but it is not the only one: the Hadamard basis {|+⟩, |−⟩}, with |±⟩ = (|0⟩ ± |1⟩)/√2, is equally valid, and a state that is a superposition in one basis can be a basis state in another — |+⟩ is 'both 0 and 1' in the computational basis but perfectly definite in the Hadamard basis.For n qubits, the computational basis has 2ⁿ states, |00...0⟩ through |11...1⟩, one for each classical bit string.Basis states matter operationally: a measurement is always defined with respect to a basis, and its possible outcomes are exactly the basis states.Choosing the right basis is a recurring trick in quantum algorithms and quantum communication.Everyday analogy
Common misconceptions
- The computational basis {|0⟩, |1⟩} is NOT the only basis — any pair of orthonormal qubit states forms a valid basis, and whether a state 'is in superposition' depends on which basis you describe it in.
- A basis state is not the same as a 'ground state' — in quantum computing, 'basis state' refers to a member of a chosen reference set (usually the computational basis), not to the lowest-energy state of a physical system, even though hardware often encodes |0⟩ as the ground state.
- Having 2ⁿ basis states does NOT mean an n-qubit register stores 2ⁿ readable values — a measurement returns only one n-bit outcome.
Key takeaways
- Basis states are orthonormal (⟨i|j⟩ = δᵢⱼ) and span the state space: every state is a unique linear combination of them.
- The computational basis {|0⟩, |1⟩} corresponds to classical bit values, but other bases such as {|+⟩, |−⟩} are equally valid.
- Superposition is basis-relative: |+⟩ is a superposition in the computational basis yet a definite basis state in the Hadamard basis.
- An n-qubit system has 2ⁿ computational basis states, one for each classical bit string.
Check your understanding
How many computational basis states does a 3-qubit system have?
- A.3
- B.6
- C.8
- D.9
Show the answer
Answer: C. 8
Why: An n-qubit system has 2ⁿ computational basis states. For n = 3 that is 2³ = 8 states: |000⟩, |001⟩, |010⟩, |011⟩, |100⟩, |101⟩, |110⟩, |111⟩.
Builds on
Primary source: Nielsen & Chuang, Quantum Computation and Quantum Information (2010), doi:10.1017/CBO9780511976667
Graded 2026-07-10 (human sign-off): established — orthonormal bases and the computational basis per Nielsen & Chuang (2010) §1.2/§2.1.2 and Preskill Ph219. Pending human grading.
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